0=-4.9t^2+600

Solution for 0=-4.9t^2+600 equation:

0=-4.9t^2+600

We move all terms to the left:

0-(-4.9t^2+600)=0

We add all the numbers together, and all the variables

-(-4.9t^2+600)=0

We get rid of parentheses

4.9t^2-600=0

a = 4.9; b = 0; c = -600;
Δ = b2-4ac
Δ = 02-4·4.9·(-600)
Δ = 11760
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11760}=\sqrt{784*15}=\sqrt{784}*\sqrt{15}=28\sqrt{15}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-28\sqrt{15}}{2*4.9}=\frac{0-28\sqrt{15}}{9.8}
=-\frac{28\sqrt{15}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+28\sqrt{15}}{2*4.9}=\frac{0+28\sqrt{15}}{9.8}
=\frac{28\sqrt{15}}{9.8}
$